At 60 Celsius , 123 grams of NaNO3 is dissolved in 100 grams of water. What is the Molarity of this solution?

CHAPTER 17

PROPERTIES OF SOLUTIONS

Solution Composition

12. Mass percent: the percent by mass of the solute in the solution.

Mole fraction: the ratio of the number of moles of a given component to the total number of

moles of solution.

Molarity: the number of moles of solute per liter of solution.

Molality: the number of moles of solute per kilogram of solvent.

Volume is temperature-dependent, whereas mass and the number of moles are not. Only

molarity has a volume term, so only molarity is temperature-dependent.

13. a. HNO3(l) → H+

(aq) + NO3

−

(aq) b. Na2SO4(s) → 2 Na+

(aq) + SO4

2−

(aq)

c. Al(NO3)3(s) → Al3+(aq) + 3 NO3

−

(aq) d. SrBr2(s) → Sr2+(aq) + 2 Br−

(aq)

e. KClO4(s) → K+

(aq) + ClO4

−

(aq) f. NH4Br(s) → NH4

+

(aq) + Br−

(aq)

g. NH4NO3(s) → NH4

+

(aq) + NO3

−

(aq) h. CuSO4(s) → Cu2+(aq) + SO4

2−

(aq)

i. NaOH(s) → Na+

(aq) + OH−

(aq)

14. Mol Na2CO3 = 0.0700 L ×

L

3.0 mol Na 2CO3 = 0.21 mol Na2CO3

Na2CO3(s) → 2 Na+

(aq) + CO3

2−

(aq); mol Na+

= 2(0.21) = 0.42 mol

Mol NaHCO3 = 0.0300 L ×

L

1.0 mol NaHCO3 = 0.030 mol NaHCO3

NaHCO3(s) → Na+

(aq) + HCO3

−

the answer is true.