A sample of gas is held at 100oc at a volume of 20 L. if the volume is increased to 40 L what is the new temperature of the gas in celcius.

473°C

Explanation:

We'll begin by analysing what was given from the question. This is illustrated below:

Initial temperature (T1) = 100°C

Initial volume (V1) = 20 L

Final volume (V2) = 40 L

Final temperature (T2) =?

Next, we shall be converting the temperature in celsius to Kelvin temperature. This is illustrated below:

Temperature (Kelvin) = temperature (celsius) + 273

Initial temperature (T1) = 100°C = 100°C + 273 = 373K

Next, we shall obtain the new temperature by applying the Charles' law equation. This is illustrated below:

V1/T1 = V2/T2

20/373 = 40/T2

Cross multiply to express in linear form

20 x T2 = 373 x 40

Divide both side by 20

T2 = (373 x 40) /20

T2 = 746K

Next, we shall be converting the new temperature obtained from Kelvin to celsius temperature. This is illustrated below:

Temperature (celsius) = Temperature (Kelvin) - 273

Temperature (celsius) = 746K - 273

Temperature (celsius) = 473°C