A glucose solution (C₆H₁₂O₆₎ has 90 g of glucose in a 500 ml flask. What is the molarity?

1 mol / cm³

Explanation:

Mass of solute = 90g

Volume of solvent = 500mL

1mL = 1cm³

500mL = 500cm³

Molarity = no. Of moles of solute / volume of solvent

No. Of moles of solute = mass / molarmass

Molar mass of glucose C₆H₁₂O₆ = [(12*6) + (1*12) + (16*6)]

Molar mass of glucose = (72 + 12 + 96) = 180g/mol

No. Of moles of glucose = 90 / 180 = 0.5 moles

If 0.5 moles is present in 500cm³

X moles will be present in 1000cm³

= (1000 * 0.5) / 500

= 1 mol/cm³

The molarity of glucose is 1 mol/cm³

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

a:

by the combination of an unlimited number of elements