Determine the amount of heat energy in joules required to raise the temperature of 7.40g of water from 29.0OC to 46.0 OC.

The amount of heat energy will be "526 J".

Given:

Mass,

Initial temperature,

Final temperature,

Change in temperature,

The amount of heat energy,

→

By substituting the values, we get

Thus the above answer is right.

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The amount of heat energy in joules required to raise the temperature is 526 Joules

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q = Heat absorbed = ?

m= mass of substance = 7.40 g

c = specific heat capacity =

Initial temperature of the water = = 29.0°C

Final temperature of the water =  = 46.0°C

Change in temperature ,

Putting in the values, we get:

The amount of heat energy in joules required to raise the temperature is 526 Joules

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.