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A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate the empirical formula of the chromium sulfide.
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Express the following number in scientific notation. 0.026890 =
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How many moles are in 7.2 x 10^23 carbon molecules? (*round to the nearest hundredth and include the unit "mol c" after your number) question 6 options:
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Which factor is likely to impact the possible number of compounds ?
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A 0.500-g sample of chromium metal reacted with sulfur powder to give 0.963 g of product. Calculate...
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