How many moles of ammonia would be required to react exactly with 0.470 moles of cooper (ll) oxide in the following chemical reaction? 2 NH₃ (g) + 3 CuO (s) → 3 Cu (s) + N₂ (g) + 3H₂O (g)

0.313 mole of NH3

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2NH3(g) + 3CuO(s) → 3Cu(s) + N2(g) + 3H2O(g)

The number of mole of ammonia (NH3) required to react with 0.470 mole of copper(ll) oxide (CuO) can be obtained as follow:

From the balanced equation above,

2 moles of NH3 reacted with 3 moles of CuO.

Therefore, Xmol of NH3 will react with 0.470 mole of CuO i.e

Xmol of NH3 = (2 x 0.470) /3

Xmol of NH3 = 0.313 mole.

Therefore, 0.313 mole of NH3 is needed for the reaction

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.