C(s)+ 1 /2 O 2 (g) CO(g) CO(g)+ 1 /2 O 2 (g) CO 2 (g) How will oxygen appear in the final chemical equation?

Answer : The oxygen will appears in the final chemical equation as a reactant.

Explanation :

The given chemical reactions are:

(1)

(2)

Now we are adding reaction 1 and reaction 2, we get the final chemical equation.

The final chemical equation is:

Thus, the oxygen will appears in the final chemical equation as a reactant.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%