The final solution had a volume of 1.0L and a molarity of 0.925. How many moles of Nickel (II) chloride were present in the solution? Show your work.

0.925 mole

Explanation:

From the question given, the following were obtained:

Volume = 1.0L

Molarity = 0.925 M

Number of mole of Nickel (II) chloride =?

Molarity is simply defined as the mole of solute per unit litre of the solution.

It is represented mathematically as:

Molarity = mole /Volume

With the above equation, we can easily find the mole of Nickel (II) chloride present in the solution as follow:

Molarity = mole /Volume

0.925 = mole / 1

Mole = 0.925 x 1

Mole of Nickel (II) chloride = 0.925 mole

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).