The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step provide a numerical answer. A solution is made by combining 300mL of 0.020M trimethyl amine, that is (CH3)3N and a 500mL of a 0.03M solution of it's conjugate acid, that is (CH3)3NH . The Kb for trimethyl amine is 6.3x10-5. The Henderson-Hasselbalch equation uses pKa not Kb, Calculate the pKa

The pKa is 13.0.

Explanation:

pKa + pKb = 14

Given, Kb of trimethylamine = 6.3 ×

pKb = - log (6.3 × )

= 1.0

⇒ pKa = 14 - pKb = 14 - 1.0

pKa = 13.0

Check: For most weak acids,  pKa ranges from 2 to 13.

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the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.