Consider the following system at equilibrium:
N2(g)+3H2(g)-2NH3(g)

What will happen to this system if 1.00 mol N subscript 2 is suddenly added?

Group of answer choices

The additional collisions between N subscript 2 and H subscript 2 molecules increases the rate in the forward direction and produces more N H subscript 3

The concentrations of each molecule would increase relative to the original amount present.

As the concentration of N H subscript 3 increases, equilibrium shifts to the left and increases H subscript 2 concentration.

The sudden change in the amount of N subscript 2 increases the rate in the reverse direction to compensate and produce more H subscript 2.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole