What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg

The temperature would be 922.01 °K

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P*V=n*R*T

Where P is the gas pressure, V is the volume it occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

Replacing:

2300 mmHg* 15 L=0.6 moles*62.36367   *T

Solving:

T= 922.01 °K

The temperature would be 922.01 °K

8 carbon atoms forming single bonds with 18 hydrogen atoms; a triple bond exists between the third and fourth carbon atom from the right

explanation:

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