Hydrogen peroxide, H2O2, decomposes according to the equation above. This reaction is thermodynamically favorable at room temperature.

(a) A particulate representation of the reactants is shown below in the box on the left. In the box below on the right, draw the particulate representation of all the molecules that would be produced from these four reactant molecules.

4H₂O₂ → 4H₂O + 2O₂

The chemical reaction for the decomposition of hydrogen peroxide can be represented as follows;

2H₂O₂ → 2H₂O + O₂

Therefore, two molecules of hydrogen peroxide decomposes into two molecules of water and one molecule of oxygen.

A wide variety of organic compounds spontaneously form peroxides by a free radical reaction of the hydrocarbon with molecular oxygen.

In given diagram, we have 4 molecules of hydrogen peroxide decomposing, therefore we have;

4H₂O₂ → 4H₂O + 2O₂

The attached diagram shows the products of the decomposition of the four molecules of hydrogen peroxide.

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4H₂O₂ → 4H₂O + 2O₂

Explanation:

The chemical reaction for the decomposition of hydrogen peroxide can be represented as follows;

2H₂O₂ → 2H₂O + O₂

Therefore, two molecules of hydrogen peroxide decomposes into two molecules of water and one molecule of oxygen.

In a related diagram, we have 4 molecules of hydrogen peroxide decomposing, therefore we have;

4H₂O₂ → 4H₂O + 2O₂

The attached diagram shows the products of the decomposition of the four molecules of hydrogen peroxide.