Using the following thermochemical equation, determine the amount of heat produced per kg of CO2 formed during the combustion of benzene (C6H6).

2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔH°rxn = -6278 kJ

1.189 × 10⁴ kJ of heat are produced per kg of CO₂ formed during the combustion of benzene.

Let's consider the following thermochemical equation for the combustion of benzene.

2 C₆H₆(l) + 15 O₂(g) → 12 CO₂(g) + 6 H₂O(g)   ΔH°rxn = -6278 kJ

First, we will convert 1 kg (1000 g) of CO₂ to moles using its molar mass (44.01 g/mol).

Considering the standard enthalpy of the reaction given in the thermochemical equation, 6278 kJ of heat are released when 12 moles of CO₂ are produced. The heat released when 22.72 moles of CO₂ are produced is:

1.189 × 10⁴ kJ of heat are produced per kg of CO₂ formed during the combustion of benzene.

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 12033 kJ of heat produced per kg of formed during the combustion of benzene

Explanation:

The balanced chemical equation for combustion of benzene is :

  = -6278 kJ

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and for the reaction comes out to be negative.

     (1kg=1000g)

According to stoichiometry :

12 moles of on combustion produce heat = 6278 kJ

Thus 23 mole of on combustion produce heat =

Thus 12033 kJ of heat produced per kg of formed during the combustion of benzene

law of conservation of matter

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.