Identify the correct set-up. How many moles of aluminum oxide would form if 25.0 g of aluminum react completely given the following chemical reaction: 4Al + 3O₂ → 2Al₂O₃?

Option 1. 25g Al x 1mol Al/26.982g Al x 2mol Al₂O₃/ 4mol Al

Explanation:

The equation for the reaction is given below:

4Al + 3O₂ → 2Al₂O₃

Molar Mass of Al = 26.982g/mol

Mass of Al = 25g

The number of mole in 25g of Al can be expressed as:

25g of Al = 25g x 1 mol / 26.982g

From the balanced equation above,

4 mol of Al produced 2 moles of Al₂O₃.

Therefore, 25g of Al (25g x 1 mol / 26.982g) will produce =

25g Al x 1mol Al/26.982g Al x 2mol Al₂O₃/ 4mol Al

beta decay is the answer