Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 ∘C . Cu(s) || Cu2+(0.14 M) ‖‖ Fe2+(0.0040 M) || Fe(s) E∘Cu2+/Cu=0.339 VE∘Fe2+/Fe=−0.440 V Ecell= V Is the electrochemical cell spontaneous or not spontaneous as written at 25 ∘C ? not spontaneous spontaneous Calculate the potential of the electrochemical cell and determine if it is spontaneous as written at 25 ∘C . Pt(s) || Sn2+(0.0067 M),Sn4+(0.11 M) ‖‖ Fe3+(0.15 M),Fe2+(0.0019 M) || Pt(s) E∘Sn4+/Sn2+=0.154 VE∘Fe3+/Fe2+=0.771 V Ecell= V Is the electrochemical cell spontaneous or not spontaneous as written at 25 ∘C ? spontaneous not spontaneous
Answers: 2
is negative
![Pt || Sn^{2+} (0.0067 M) || Sn^{4+} (0.11 M) | Fe^{3+}(0.15 M)\\Sn^{2+} + 2Fe^{3+} \rightarrow Sn^{4+} + 2Fe^{2+} (aq)\\ E_{cell} ^{0} = E_{anode} ^{0} - E_{cathode} ^{0}\\E_{cell} ^{0} = E_{Fe^{3+}/Fe^{2+} } ^{0} - E_{Sn^{4+}/Sn{2+}} ^{0}\\E_{cell} ^{0} = 0.771 - 0.154\\E_{cell} ^{0} = 0.617 V\\E_{cell} = E_{cell} ^{0} - \frac{0.0591}{n} log(\frac{[Fe^{2+}]^2 [Sn^{4+}]}{[Fe^{3+}]^2 [Sn^{2+}] } )\\E_{cell} = 0.617 - \frac{0.0591}{2} log(\frac{0.0019^2 * 0.11}{0.15^2 * 0.154 } )\\E_{cell} = 0.733 V](/tpl/images/0642/3814/7df54.png)
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