Determine the number of moles in a 1.50 L sample of 0.625 M solution of NaCl.

0.9375 mole

Explanation:

Data obtained from the question include:

Volume of solution = 1.50L

Molarity of NaCl = 0.625 M

Mole of NaCl =..?

The molarity of a solution is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:

Molarity = mole /Volume

With the above equation, the number of mole of NaCl in the solution can be obtained as follow:

0.625 = mole / 1.5

Cross multiply to express in linear form

Mole = 0.625 x 1.5

Mole = 0.9375 mole

Therefore, 0.9375 mole of NaCl is present in the solution.

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b