If the molar heat of fusion of water is 6.01

kJ

mol

, how much heat energy was required to melt 2 kg of ice?

Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ

Explanation :

First we have to calculate the moles of ice.

Now we have to calculate the heat energy.

As, heat energy required to melt 1 mole of ice = 6.01 kJ

So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ

                                                                                  = 667.7 kJ

Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ

a plasma is a warm ionized gasoline consisting of approximately equal numbers of definitely charged ions and negatively charged electrons. the characteristics of plasmas are notably unique from the ones of ordinary neutral gases in order that plasmas are considered a awesome "fourth kingdom of remember."