Mezclamos 0.08 moles de ácido cloroacético (ClCH2COOH) y 0.04 moles de
cloroacetato sódi...
Chemistry, 07.05.2020 05:12 bbostter1131
Mezclamos 0.08 moles de ácido cloroacético (ClCH2COOH) y 0.04 moles de
cloroacetato sódico (ClCH2COONa) en 1.0 L de agua (pKa = 2.865).
a. Calcula el pH
si. Calcula el pH usando las formas formales (actividades). Tener en
cuenta el aporte de los protones (apartado a) en el cálculo de la fuerza iónica.
C. Hallar el pH de una mezcla preparada disolviendo los siguientes compuestos
en un volumen final de 1L: 0.08 moles de ClCH2COOH, 0.04 moles de
ClCH2COONa, 0.05 moles de HNO3 y 0.06 moles de NaOH
Answers: 1
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