The energy content of food is typically determined using a bomb calorimeter. Consider the combustion of a 0.22-g sample of butter in a bomb calorimeter having a heat capacity of 2.67 kJ/°C. If the temperature of the calorimeter increases from 23.5°C to 26.1°C, calculate the energy of combustion per gram of butter. Energy of combustion = kJ/g

The energy of combustion of butter is 31.5 kJ/g

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q = Heat absorbed by calorimeter =?

C = heat capacity of calorimeter =

Initial temperature of the calorimeter  = =

Final temperature of the calorimeter  =  =

Change in temperature ,

Putting in the values, we get:

As heat absorbed by calorimeter is equal to heat released by combustion of butter

Heat released by 0.22 g of butter = 6.94 kJ

Heat released by 1g of butter =

The energy of combustion of butter is 31.5 kJ/g

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explanation:

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error