The addition of 5.0x10–3 total moles of Zn2+ to a 1.0 L solution of NaCN gives a solution of the complex ion [Zn(CN)4] 2– (Kf = 4.17x1019). What is the equilibrium concentration of uncomplexed Zn2+ ions if the concentration of cyanide ions at equilibrium is 0.50 M?

Concentration of = 1.9 *

Explanation:

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