What volume would 32.0 g of NO2 gas occupy at 3.12 atm and 18.0 Celsius

Volume of 32.0 g at 3.12 atm and 18.0 is 5.33 L.

Explanation:

Molar mass of = 46.0055 g/mol

So, 32.0 g of = mol of = 0.696 mol of

Let's assume behaves ideally.

Then    , where P, V, n, R and T represents pressure, volume, number of moles, gas constant and temperature (in kelvin scale) respectively.

Here = 3.12 atm, = 0.696 mol, R = 0.0821 L.atm/(mol.K) and T = (273+18.0)K = 291 K

So,      

        or,

        or,

So, volume of 32.0 g at 3.12 atm and 18.0 is 5.33 L.

1 is the answer to this problem