How many kilojoules of heat are required to vaporize 50.0 g of ethanol (MM = 46.07 g). Its molar heat of vaporization is 43.5 kJ/mol.

ΔH = 41.7 kj

Given data:

Mass of ethanol = 50 g

Heat required to vaporize = ?

Boiling point of ethanol = 78.3°C

Molar heat of vaporization = 38.6 kj/mol

Solution:

First of all we will calculate the number of moles.

Number of moles = mass / molar mass

Number of moles = 50 g/ 46.07 g/mol

Number of moles = 1.08 mol

ΔH = 38.6 kj/mol ×1.08 mol

ΔH = 41.7 kj

Explanation:

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

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