How many liters of 4.0 M NaOH solution will react with 1.8 mol H2SO4? (Remember to balance the equation.

14.4 L

Explanation:

2 NaOH + H2SO4  -> Na2SO4 + H2O

2 mol NaOH -> 1 mol H2SO4

         x  - > 1.8 mol H2SO4      x= (1.8 mol H2SO4 * 2 mol NaOH)/ 1 mol H2SO4      

                                                  x= 3.6 mol NaOH

M= mol solute/ L solution

L solution = mol solute/ M       L solution = (3.6 mol NaOH)/4.0 M

                                                 L solution = 14.4 L

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.