Consider LiBr → Li+ + Br- and the following information.
AHlat = -803 kJ/mol
AHhydr of Br- = -284 kJ/mol
AH sol = -47 kJ/mol
What is the AH nydr of Lit? Use AH sol =-^Hlat + XHnydr.
-570 kJ/mol
-566 kJ/mol
470 kJ/mol
472 kJ/mol

1 is the answer to this problem

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally