Chemistry, 19.05.2020 03:19 victoria6929
How much NaOH (in grams) is needed to prepare 463 mL of solution with a pH of 10.020?
Answers: 1
of NaOH ![pH=-\log [H^+]](/tpl/images/0654/5623/37e81.png)
![10.020=-\log[H^+]](/tpl/images/0654/5623/218d3.png)
![[H^+]=9.55\times 10^{-11}](/tpl/images/0654/5623/d0b6b.png)
![[H^+][OH^-]=10^{-14}](/tpl/images/0654/5623/7d81f.png)
![[OH^-]=\frac{10^{-14}}{9.55\times 10^{-11}}=1.05\times 10^{-4}M](/tpl/images/0654/5623/b998a.png)
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How much NaOH (in grams) is needed to prepare 463 mL of solution with a pH of 10.020?...
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