The diagram shows a Zn/MnO2-KOH alkaline dry cell.
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In your response, do the following:
Label all parts.
Label the cathode and the anode, including the charges on each.
Show the flow of electrons.
Explain how the cell works. Include the oxidation and reduction half-reactions in your explanation.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;