1
Identify how many Sulfur atoms are in the product of this chemical
equation *
BaSO4 + H2SO4
Ba(HSO4)2
O A. 2
O B.4
O C. 8
O D. Unknown

2

Explanation:

Equation of reaction

BaSO₄ + H₂SO₄ → Ba(HSO₄)₂

From the above equation of reaction, it is evident that there are 2 atoms in the product side of the reaction which is only logical because every chemical reaction obey the law of conservation of mass which states that matter can neither be created nor destroyed but can changed from one form to another.

In the reactant side, we have 2 atoms of S from the two reactants coming together.

One sulfur atom from BaSO₄ and the other from H₂SO₄. So therefore, only 2 sulfur can be produced since the reaction has to observe law of conservation of matter

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.