If you want to produce 11 moles of NH3, how much H2 do you need?

33 g of H2

Explanation:

N2 + 3 H2 -> 2 NH3

3 mol H2 -> 2 mol NH3

             x -> 11 mol NH3

x= (11 mol NH3 * 3 mol H2)/ 2 mol NH3

x= 16.5 mol H2

1 mol H2    -> 2 g

16.5 mol H2 ->x

x= (16.5 mol H2 * 2 g)/ 1 mol H2

x= 33 g

i would say b

explanation:

but i think i would need more information than that