He volume of N2 gas is 500 mL at the temperature of 10 ℃ at 108 kPa. What will be the new pressure if the volume increased to 750 mL and the temperature increased at 21 ℃? Please quickly help

The new pressure will be 74.8 kPa

Explanation:

Step 1: Data given

Volume of the N2 gas = 500 mL = 0.500 L

Temperature = 10.0 °C = 283 K

Pressure = 108 kPa

The volume is increased to 750 mL = 0.750 L

The temperature is increased to 21.0 °C = 294 K

Step 2: Calculate the new pressure

P1*V1 / T1 = P2*V2 / T2

⇒with P1 = the initial pressure = 108 kPa

⇒with V1 = the initial volume = 0.500 L

⇒with T1 = the initial temperature = 283 K

⇒with P2 = the new pressure = TO BE DETERMINED

⇒with V2 = the increased volume = 0.750 L

⇒ with T2 = the increased temperature = 294 K

108 * 0.500 / 283 = P2 * 0.750 / 294

P2 = (108*0.500 * 294) / (283*0.750)

P2 = 74.8 kPa

The new pressure will be 74.8 kPa

a plasma is a warm ionized gasoline consisting of approximately equal numbers of definitely charged ions and negatively charged electrons. the characteristics of plasmas are notably unique from the ones of ordinary neutral gases in order that plasmas are considered a awesome "fourth kingdom of remember."

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.