A gas has a volume of 45.0 mL and a pressure of 760.0 mm. If the pressure increased to 850.0 mm and the temperature remained the same, what would be its new volume?

40 mL

Explanation:

V2=P1V1/P2

You can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.