How many grams of oxygen are required to produce
9 grams of water at standard conditions?
2 H, + O2 → 2 H2O
grams?

8 GRAMS OF OXYGEN WILL BE REQUIRED TO PRODUCE 9 GRAMS OF WATER MOLECULES.

Explanation:

The equation for the reaction is;

2 H + O2 > 2 H2O          

(H = 1, O = 16)

From the reaction, it can be observed that 1 mole of O2 reacts to form 2 moles of H2O

At STP, using the molar masses of the elememts and compound in the reaction, 32 g of O2 will reacts to form 36 g (18 * 2 g) of H2O

32 g of O2 = 36 g OF H2O

if 9 grams of H2O is produced, the mass of oxygen required to produce it will be:

( 32 * 9 / 36 ) g of O2

= (288 / 36) g

= 8 g of O2

So, 8 grams of Oxygen will be required to produce 9 grams of water.

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