A helium filled balloon has a volume of 2.48L and a pressure of 150kpa the volume of the balloon increases to 2.98L what is the new pressure of the helium gas

THE NEW PRESSURE OF THE HELIUM GAS IS 124kPa AFTER THE VOLUME WAS INCREASED FROM 2.48 L TO 2.98 L

Explanation:

Using Boyle's law which states that at constant temperature, the pressure of a given gas is inversely proportional to the volume occupied by the gas.

Mathematically,

P1 V1 = P2 V2

P1 = 150 kPa = 150 * 10^3 Pa

V1 = 2.48 L

V2 = 2.98 L

P2 = ?

Rearranging the formula making P2 the subject of the equation, we obtain;

P2 = P1 V1 / V2

P2 = 150 * 10^3 * 2.48 / 2.98

P2 = 372 * 10 ^3 / 2.98

P2 = 124.83 * 10^3 Pa or 124.8kPa

In other words, the new pressure of the helium gas after its volume was increased from 2.48 L to 2.98 L is 124.8kPa.

5.6⋅10−^19  j

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