How many moles of pb(no3)2 are required if 8 moles of alcl3 are consumed?

12 moles of Pb(NO3)2

Explanation:

We'll begin by writing the balanced equation for the reaction.

This is illustrated below:

3Pb(NO3)2 + 2AlCl3 —> 3PbCl2 + 2Al(NO3)3

From the balanced equation above, 3 moles of Pb(NO3)2 required 2 moles of AlCl3.

Therefore, Xmol of Pb(NO3)2 will require 8 moles of AlCl3 i.e

Xmol of Pb(NO3)2 = (3 x 8)/2

Xmol of Pb(NO3)2 = 12 moles.

Therefore, 12 moles of Pb(NO3)2 are required for the reaction.

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