When 10 moles of O₂ reacts with 1.4 moles of C₁₀H₈ what is the limiting reactant? *

O2 is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C10H18 + 29O2 —> 20CO2 + 18H2O

The limiting reactant can be obtained as follow:

From the balanced equation above,

2 moles of C10H18 reacted with 29 moles of O2.

Therefore, 1.4 mole of C10H18 will react with = (1.4 x 29)/2 = 20.3 moles of O2.

From the above calculation, we can see that it will take a higher amount of O2 i.e 20.3 moles than what was given i.e 10 moles to react completely with 1.4 mole of C10H18. Therefore, O2 is the limiting reactant and C10H18 is the excess reactant.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

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where are the choice options?