Medical implants and high-quality jewelry items for body piercing are frequently known by a trade name, G23Ti, which means "surgical-grade" titanium. It is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.

What is the empirical formula that represents this material?

Ti6Al4V1 or Ti6Al4V

Explanation:

So, from the question above we are given the following Important data or parameters or information which is going to help us in solving this question and they are;

The "surgical-grade" titanium is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.

This is a stoichiometry Question so in order to be able to solve this question one must have the basic knowledge of stoichiometry, it is advisable that one revise it.

So, let us delve right into the solution of this question. Recall that, the formula for Calculating the number of moles = mass/molar mass.

Hence, the number of moles of titanium,Ti = 64.3/47.87 = 3 moles.

Also, the number of moles of aluminum = 24.19/26.98 = 0.8966

For vanadium; 11.42/51 = 0.22

The next step is to divide each number of moles component by the lowest number of mole, that is;

Ti = 1.34/ 0.22 = 6; Al = 0.8966/0.22= 4 and V = 0.22/0.22 = 1.

Thus, the emperical formula is = Ti6Al4V.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l