Chemistry, 22.05.2020 07:59 jyfye6918

In the reaction H2S + NH3 NH4+ + HS–, the two Brönsted-Lowry bases are

A) NH3 and HS-

B) NH3 and NH4+

C) H2S and NH3

D) H2S and HS-

Answers: 2

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Answer from: rb276

Option A is correct.

The two Brönsted Lowry bases are NH₃ and HS⁻.

Explanation:

In any neutralization reaction or any reaction that seems like a neutralization reaction, the Bronsted Lowry Acid is the specie that donates a proton in reaction, the base is the specie that accepts the donated proton in the reaction.

The acid, after donating the proton becomes the conjugate base, and the base after receiving the proton becomes a specie known as the conjugate acid.

In this reaction, H₂S (acid) loses a proton to NH₃ (base) to form a HS⁻ (conjugate base) and NH₄⁺ (conjugate acid).

In a backward reaction, the conjugate acid and conjugate base form the acid and base pair respectively as required.

Hence, the two two Brönsted-Lowry bases are NH₃ and HS⁻.

Hope this Helps!!!

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

4- c, because all matter stays the same no matter what. it is still there. 5- b, because matter is known as mass. 6-c because, flammability is a chemical property. malleability is changing the shape of an object.

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