50 points !! for this question
On the picture

Here's what I get  

Explanation:

1. At 0 mL HCl

pOH = -log[OH⁻] = -log(0.125) = 0.90

pH = 14.00 - pOH = 14.00 - 0.90 = 13.10

2. At 10 mL HCl

Initial moles NaOH = 25.0 mL × 0.125 mmol/mL = 3.125 mmol NaOH

Moles HCl added = 10 mmol × 0.0625 mmol/L = 0.625 mmol HCl

Moles NaOH remaining = (3.125 - 0.625) mmol = 2.50 mmol NaOH

Total volume = (25.0 + 10) mL= 35.0 mL

[OH⁻] =2.50/35 = 0.071 43 mol·L⁻¹

pOH = 1.15

pH = 12.85

3. At 50 mL HCl

Initial moles NaOH = 3.125 mmol NaOH

Moles HCl added =3.125 mmol HCl

Moles NaOH remaining = 0

We are at the equivalence point.

pH = 7.00

4. At 70 mL HCl

Initial moles NaOH = 3.125 mmol NaOH

Moles HCl added =4.375 mmol HCl

Excess moles HCl = 1.25 mmol HCl

Total volume = 95 mL

[H⁺] = 0.013 16 mol·L⁻¹

pH = 1.88

5. Table

7. Titration Curve

See below.

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.