How many moles of barium hydroxide can be produced from the reaction of 4.234 moles of barium with 8.902 moles of water according to the following reaction? Ba + 2 H2O Ba(OH)2 + H2

Thus 4.234 moles of will be produced from the given masses of both reactants.

Explanation:

The balanced chemical reaction is :

According to stoichiometry :

1 mole of require =  2 moles of

Thus 4.234 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent as it is present in more amount than required.

As 1 mole of give = 1 mole of

Thus 4.234 moles of will give =  of

Thus 4.234 moles of will be produced from the given masses of both reactants.