How many milliliters of a 4.0-molar solution
of HCl are needed to completely neutralize
60 milliliters of a 3.2-molar solution of NaOH?

HCl + NaOH → NaCl + H2O

No. of moles of NaOH = MV/1000

= 3.2X60/1000

= 0.192 mol

**M is your concentration of solution, V is the volume of solution either in cm³ or mL cuz they are equal**

1 mol of NaOH reacted with 1 mol of HCl. No. of moles of HCl needed to react with 0.192mol of NaOH

= 0.192x1/1

= 0.192mol

Volume of HCl = no. of moles x 1000 / M

= 0.192 x 1000 / 4.0

= 48mL