Given the information shown in process "B", calculate the molar enthalphy of fusion for ice

A) 40.1 kJ/mol
B) 4.50 kJ/mol
C) 18.0 kj/mol
D) 6.02 kJ/mol

D) 6.02 kJ/mol

Explanation:

Hello,

In this case, since 200kJ melted 1.5 kg of ice (2.0kg-0.5kg), we can compute the melted moles:

Then, we compute the molar enthalpy of fusion by diving the melted moles to the applied heat:

Hence answer is D) 6.02 kJ/mol.

Best regards.

the ratio of the conjugate base to the acid required to attain the desired ph.