When 481 J of energy is added to 18.3 g of aluminum at 17.4°C, the temperature increases

to 46.6°C. What is the specific heat of aluminum?

THE SPECIFIC HEAT OF ALUMINIUM IS 0.900 Jg^-1K^-1

Explanation:

To solve this question, follow the following steps listed below:

1. Write the formulae for heat change in a reaction

Heat = m c ΔT

2. Write out their values and convert to standard units.

m = mass of aluminum = 18.3g

Heat = 481 J

T2 = final temperature = 46.6°C = 273 + 46.6 = 319.6 K

T1 = initial temperature = 17.4 °C = 17.4 + 273 K = 290.4K

C = specific heat capacity of aluminum = ?

3. Solve for the specific heat of aluminium

c = Heat / m ΔT

c = 481 J / 18.3 g * ( 319.6 - 290.4) K

c = 481 / 18.3 * 29.2

c = 481 / 534.36

c = 0.900 Jg^-1K^-1

In conclusion, the specific heat capacity of aluminum is 0.900 Jg^-1K^-1.

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- lead + phosphoric acid = hydrogen + lead(ii) phosphate