What is the molarity of a solution of sulfuric acid if 49.0 mL of it are neutralized by a titration

of 68.4 mL of 0.333 M sodium hydroxide solution? (Round to the correct number of sig figs

and include your units!)

Explanation:

Hello,

In this case, since the reaction between sulfuric acid and sodium hydroxide is:

H2SO4+2NaOH⇒Na2SO4+2H2O

We find a 1:2 molar ratio between the acid and the base, for that reason, at neutralization we verify:

That in terms of concentration and volumes:

With it, we can compute the molarity of the acid solution:

Best regards.

is there multiple choice answers?

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.