A sample of chlorine gas is held at a pressure of 1023.6 Pa. When the pressure is decreased to 811.4 Pa the volume is 25.6 L. What was the original volume?

V1 = 20.3L

Explanation:

P2 = 811.4Pa

V2 = 25.6L

P1 = 1023.6Pa

V1 = ?

To solve this question, we'll have to use Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.

Mathematically,

V = k / P, k = PV

P1 × V1 = P2 × V2 = P3 ×V3 ==Pn × Vn

P1 × V1 = P2 × V2

Solve for V1

V1 = (P2 × V2) / P1

V1 = (811.4 × 25.6) / 1023.6Pa

V1 = 20771.84 / 1023.6

V1 = 20.29 = 20.3L

The initial volume was 20.3L

a saline water is fed to a reverse osmosis unit at flow rate o rotameter connected to reject (retentate) line reads 8 installed in reject and permeate line reads 15.2 milli siemens/cm and 300 micro siemens/com respectively.