In living organisms, C-14 atoms disintegrate at a rate of 15.3 atoms per minute per gram of carbon. A charcoal sample from an archaeological site has a C-14 disintegration rate of 9.16 atoms per minute per gram of carbon. Estimate the age of this sample in years. The half-life of C-14 is 5730 years. (enter only the number of years in standard notation, not the unit years)

Rate of disintegration is defined as the time required by a sample or substance at which half of the radioactive substance disintegrates. It depends on the nature of disintegration and amount of substance.

The age of the sample is approximately 4241.17 years.

Given that:

C-14 atoms disintegration rates = 15.3 atom/ min-g

Rate of disintegration of the sample = 9.16 atom/ min-g

The digit proportion of carbon-14 is  = = 0.5987

Now, also the half-life of carbon-14 is 5730 years.

Such that:

Taking log:

n log 2 = -log 0.5987

Thus, n =

n = 0.740

The age of the sample can be given by:

Age = n x half-life

Age = 0.740 x 5730

Age = 4241.17 years.

Therefore, the age of the substance is 4241.17 years.

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The answer is "4,241 .17 years"

Explanation:

The disintegration rate, which shows in C-14 atoms =  

Rate of sample disintegration =

The digit proportion of C-14 can be determined that is included in the sample

5730 years from half-life.  

The number with half-lives (n) which are repelled must be determined:

So, the age of the sample is given by =

if you're asking what comes out, it's steam.