An SO2 sample occupies a volume of 60 ml at 318 K. At what temperature will the gas occupy a volume of 180 ml?

THE TEMPERATURE OF THE GAS AT 180 mL IS 957 K

Explanation:

This question follows Charles' law of the theory of gases. it states that the volume of a fixed mass of gas varies directly with the absolute temperature provided the pressure remains constant.

Mathematically, V1 /T1 = V2 /T2

V1 = 60 mL = 60 /1000 L = 0.06 L

T1 = 319 K

V2 = 180 mL = 180 /1000 L = 1.80 L

T2 = ?

Making T2 the subject of the formula, we have;

T2 = V2 * T1 / V1

T2 = 0.180 * 319 / 0.06

T2 = 57. 42 / 0.06

T2 = 957 K

So therefore, the temperature of the gas at a new volume of 180 mL is 957 K

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml