How many moles of gas are present in 57.20 L of argon at a pressure of 1 atm and a temperature of 0°C?

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20 POINTS

n= 2.55 moles

Explanation:

Using the formula of ideal gas law:

PV = nRT

  nRT=PV

n= PV/RT

  n= number of moles

  R= Avogadro constant = 0.0821

  T= Temperature in K => ºC + 273.15 K

  V= volume in L

  P= pressure in atm

n= (1 atm)(57.20 L) / (0.0821)(237.15 K)

n= 2.50 moles

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.