A 25.0 liter rigid container has a mixture of 32.00 grams of oxygen gas and 1 point

8.00 grams of helium gas at 298K. What is the total pressure in the

container?

= 2.94 atm

Explanation:

The total pressure () in the container is given by:

The pressure of the oxygen () and the pressure of the helium () can be calculated using the ideal gas law:

Where:

V: is the volume = 25.0 L

n: is the number of moles of the gases

R: is the gas constant = 0.082 Latm/(Kmol)

T: is the temperature = 298 K

First, we need to find the number of moles of the oxygen and the helium:

Where m is the mass of the gas and M is the molar mass

And the number of moles of helium is:

Now, we can find the pressure of the oxygen and the pressure of the helium:

Finally, the total pressure in the container is:

Therefore, the total pressure in the container is 2.94 atm.

I hope it helps you!

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