If the equilibrium concentration of CO is 3.4 × 10–1 M, and the equilibrium concentration

of H2 is 6.8 × 10–1 M, the equilibrium concentration of CH3OH is ?

4.1M = [CH₃OH]

Explanation:

The equilibrium produced for the reaction between CO and H₂ to form CH₃OH is:

CO + 2 H₂ ⇄ CH₃OH

Where Keq is defined as:

Keq = 26 = [CH₃OH] / [CO] [H₂]²

For concentrations in equilibrium

Replacing in Keq the equilibrium concentrations of CO and H₂, the equilibrium concentration of CH₃COOH is:

26 = [CH₃OH] / [3.4x10⁻¹M] [6.8x10⁻¹M]²

4.1M = [CH₃OH]

the first one is B.) At equilibrium the products are favored

the second one A.) 4.1M

mention the spill to the teacher clean the area and throw the broken pieces away

explanation:

explanation:

i think option no d is the correct answer