NEED ASAP WILL MARK BRAINLIEST ON TIMER
hi A student determines that she used 0.0665 mol of sodium hydroxide (NaOH) to completely titrate 25.00 mL of sulfuric acid solution (H2SO4). What is the molarity of the sulfuric acid?
0.00131 M
0.00262 M
1.31 M
2.62 M

The answer is 2.660 mol/l

Explanation:

Given: n= 0.0665, v= 25.00ml

Required: C

C (molarity)= n (of solute)/ v (of solvent) [ standard unit: mol/l]

First convert volume of solvent in its standard unit, i.e. litres(L)

v= 25.00ml/1000= 0.02500L

C = 0.0665 mol / 0.02500 L= 2.660 mL (In proper significant digits i.e. 4 sigdigs)

Therefore, The molarity of the sulfuric acid is 2.660 mol/L :)

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