Investigative Phenomenon
If you worked in the beverage industry, what solubility factor would you use to make the perfect fruit drink? Could an
additional factor, like diluting a concentrated drink batch make a difference in the taste as well? You will need to have
your periodic table or the virtual periodic table handy for reference
DOWNLOAD THE PERIODIC TABLE
In this laboratory activity, you will investigate how temperature agitation particle size, and dilution affect the taste of a
drink at two different molarities. 0.5 M and 10 M. You will first need to complete the Solutions Pre-Lab Questions to
get the values you need for your drink solutions. These questions are located at the top of the lab report. Then,
complete the Solutions Lab Report as you work through the steps of the lab. Be sure to review the grading rubric for
the lab before submitting your lab report. Please review this student example so that you can see how to complete a
lab report
DOWNLOAD THE SOLUTIONS PRE-LAB QUESTIONS
DOWNLOAD THE SOLUTIONS LAB REPORT

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.